18x^2+99x+108=0

Solution for 18x^2+99x+108=0 equation:

18x^2+99x+108=0

a = 18; b = 99; c = +108;
Δ = b2-4ac
Δ = 992-4·18·108
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-45}{2*18}=\frac{-144}{36}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+45}{2*18}=\frac{-54}{36}
=-1+1/2
$